LeetCode Challenge: 11. 📦 Container With Most Water - JavaScript Solution 🚀

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When it comes to solving LeetCode Problem technique to solve a greedy algorithm challenge efficiently.

Let’s dive in! 🏊‍♂️

Problem Breakdown 📝

You're given an array height where each element represents the height of vertical lines on a coordinate plane. The goal is to:

• Find two lines that, along with the x-axis, form a container holding the most water.


• Return the maximum amount of water the container can store.
  The water area between two lines is determined by:

Examples ✨

Example 1:

Example 2:

Input: height = [1,1]

Output: 1

Explanation:

The two lines are both of height 1. The width is 1, so the area is:

Final output: 49

Why It Works 🔍

• 
  Greedy Approach: Moving the pointer with the smaller height eliminates a line that would have limited the container’s capacity. This ensures we maximize the potential for a larger area.


• 
  Two-Pointer Efficiency: Only one pass is made through the array, minimizing time complexity.

🚩 Constraints Check

• The algorithm handles the edge cases, such as:
  
  
  
  
  • Height array with only two elements: Returns the correct result.
  
  
  • All heights are zero: Returns 0.
  
  
  • Varying heights: Maximizes the area.
  
  
  
  
  
  

🏆 Results

The above solution:

• Time Complexity: O(n)


• Space Complexity: O(1)

This implementation is efficient and scalable, capable of handling the upper constraint of 10^5 elements.

Final Thoughts 💡

Understanding the two-pointer technique is a game-changer for many array-based problems. This approach minimizes redundant calculations and optimizes performance.

If you enjoyed this post or have questions, let me know in the comments! 🙌

👉 Try it out and share your results below. Happy coding! 😊