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Left View of a Binary Tree

leetcode.com Problem Statement Given the root of a binary tree, return the nodes visible when the tree is viewed from the left side. Only the first node at each level is visible. …

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Problem Statement



Given the root of a binary tree, return the nodes visible when the tree is viewed from the left side.



Only the first node at each level is visible.









Brute Force Intuition



In an interview, you can explain it like this:




Perform a level-order traversal (BFS). For every level, simply record the first node encountered.




Since BFS already processes nodes level by level, identifying the first node is straightforward.






Complexity




  • Time Complexity: O(N)

  • Space Complexity: O(N)









Moving Towards the Optimal Approach



Notice that during BFS:




Each Level



Processed Together






If we know:




Level Size






then the very first node processed at that level is exactly the left view.









Pattern Recognition



Whenever you see:




  • Left View

  • Right View

  • Level Wise Processing



Think:



Level Order Traversal (BFS)









Key Observation



For every level:




First Node



Left View






Continue BFS until all levels are processed.









Optimal Approach






Step 1



Push the root into a queue.









Step 2



Process one level at a time.



For every level:




size = queue.size();












Step 3



The first node:




i == 0






belongs to the left view.









Step 4



Push:




Left Child



Right Child






into the queue.









Optimal Java Solution






class Solution {

ArrayList<Integer> leftView(Node root) {

ArrayList<Integer> ans = new ArrayList<>();

if (root == null)
return ans;

Queue<Node> q = new LinkedList<>();

q.offer(root);

while (!q.isEmpty()) {

int size = q.size();

for (int i = 0; i < size; i++) {

Node curr = q.poll();

if (i == 0)
ans.add(curr.data);

if (curr.left != null)
q.offer(curr.left);

if (curr.right != null)
q.offer(curr.right);
}
}

return ans;
}
}












Dry Run






         1
/ \
2 3
/ \ \
4 5 6









Level 1






1






First Node:




1












Level 2






2 3






First Node:




2












Level 3






4 5 6






First Node:




4






Final Answer:




[1,2,4]












Why BFS Works?



BFS processes the tree level by level.



Since nodes are visited from left to right,



the first node encountered at every level is exactly the node visible from the left side.









Complexity Analysis




















Metric Complexity
Time Complexity O(N)
Space Complexity O(N)








Interview One-Liner




Perform a level-order traversal and record the first node encountered at every level.










Pattern Learned






Level Order



First Node



Left View









Similar Problems




  • Left View of Binary Tree

  • Right View of Binary Tree

  • Top View

  • Bottom View

  • Zigzag Level Order Traversal









Memory Trick



Think:




One Level



First Node



Answer









Mental Model






Queue



Process One Level



Pick First Node



Continue






Whenever you hear:




"Left View of Binary Tree"




your brain should immediately think:



Level Order Traversal + First Node of Every Level

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