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Python Regex Explained Simply — Extract Anything From Text

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Regex sounds intimidating. It is not. Once you understand the 5 core concepts, you can extract any pattern from any text in seconds. Here is everything you need to know.






What is regex?



Regex is a pattern language. You describe what you are looking for using special characters and Python finds it for you — in any block of text, any size.



Real example: your client sends you a document with 500 customer records mixed with random text. They need all email addresses extracted into Excel. Without regex this takes hours. With regex it takes 3 lines.




CODE
import re

text = "Contact [email protected] or [email protected] for details"
emails = re.findall(r'[\w.-]+@[\w.-]+\.\w+', text)
print(emails)
# ['[email protected]', '[email protected]']









The 5 patterns you need to know






1. \d — any digit






CODE
re.findall(r'\d', 'abc123def456')
# ['1', '2', '3', '4', '5', '6']









2. \w — any word character (letter, digit, underscore)






CODE
re.findall(r'\w+', 'hello world_123')
# ['hello', 'world_123']









3. + — one or more of the previous






CODE
re.findall(r'\d+', 'price is 45000 and tax is 8100')
# ['45000', '8100']









4. [] — any character in this set






CODE
re.findall(r'[aeiou]', 'hello world')
# ['e', 'o', 'o']









5. . — any single character






CODE
re.findall(r'c.t', 'cat cut cot bat')
# ['cat', 'cut', 'cot']









The 3 functions you will use constantly






re.findall — find all matches



Returns a list of everything that matches the pattern.




CODE
text = "Prices: ₹45,000 and ₹12,500 and ₹8,750"
prices = re.findall(r'[\d,]+', text)
print(prices)
# ['45,000', '12,500', '8,750']









re.sub — find and replace



Replaces every match with something else.




CODE
messy = "phone: 98-765-43210"
clean = re.sub(r'\D', '', messy) # remove all non-digits
print(clean)
# '9876543210'









re.search — find first match



Returns just the first match with its position.




CODE
text = "Order #A12345 placed successfully"
match = re.search(r'#(\w+)', text)
if match:
print(match.group(1)) # A12345









A real data cleaning example



Client problem: they have a spreadsheet with phone numbers in 6 different formats. They need them all standardised to 10 digits.




CODE
import pandas as pd
import re

df = pd.DataFrame({
'Phone': ['9876543210', '+91-9876543210',
'(080) 4567-8901', '91 98765 43210']
})

def clean_phone(phone):
digits = re.sub(r'\D', '', phone)
if len(digits) == 10:
return digits
elif len(digits) == 12 and digits.startswith('91'):
return digits[2:]
return None

df['Clean'] = df['Phone'].apply(clean_phone)
print(df)






Output:

Phone Clean

0 9876543210 9876543210

1 +91-9876543210 9876543210

2 (080) 4567-8901 None

3 91 98765 43210 9876543210






The one-line summary



Regex is a pattern language — you describe what you are looking for and Python finds every instance of it in any text, any size.



Learn these 5 patterns and 3 functions and you can handle 90% of real data extraction gigs immediately.






Written by Raaga Priya Madhan — CSE student, Bangalore. I build Python automation and data extraction scripts. See my work on

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